Question

determine if the function f(x)=x^2+x is even, odd or neither

Answer 1

Given:

$f(x)=x^2+x$

To determine the function is even, odd, or neither,

$\begin{gathered} f(-x)=f(x)\ldots\text{.. even function} \\ f(-x)=-f(x)\ldots\text{.. Odd function} \end{gathered}$

Replace x with -x,

$f(-x)=(-x)^2+(-x)=x^2-x$

It shows that the given function is neither even nor odd.