Part 1.
In this case, we have that
[tex]\frac{1}{x}\times1\frac{5}{7}=\frac{54}{7}[/tex]where x denotes the unknown number. Since the mixed number
[tex]1\frac{5}{7}=\frac{7\cdot1+5}{7}=\frac{12}{7}[/tex]our equation can be writen as
[tex]\frac{1}{x}\times\frac{12}{7}=\frac{54}{7}[/tex]By multipliying both sides by 7, we have
[tex]\frac{1}{x}\times12=54[/tex]and by dividing both sides by 12, we get
[tex]\begin{gathered} \frac{1}{x}=\frac{54}{12} \\ \text{then} \\ \frac{1}{x}=\frac{27}{6}=\frac{9}{2} \end{gathered}[/tex]which means that
[tex]x=\frac{2}{9}[/tex]so, the missing number for the first question is 2/9
Part 2.
In this case, we have
[tex]\frac{x}{3}\times2\frac{1}{2}=\frac{25}{3}[/tex]which can be rewriten as
[tex]\frac{x}{3}\times\frac{5}{2}=\frac{25}{3}[/tex]By multiplying by 3 both sides, we have
[tex]x\times\frac{5}{2}=25[/tex]and by multiplying by 2 and dividing by 5 both sides, we get
[tex]\begin{gathered} x=25\times\frac{2}{5} \\ x=5\times2 \\ x=10 \end{gathered}[/tex]so the answer to the second question is 10
Part 3.
In this case, we have
