Question

You spin a spinner that is equally divided into 11 parts. 3 parts are green , 3 parts are white , 3 parts are speckled, and 2 parts are yellow . After that , you roll a number cube one time. What is the probability of the spinner stopping at a green section and then rolling a 3?

Answer 1

A: spinner stopping at a green section

B: rolling a 3

the spinner is divided into 11 parts, 3 of them are green, then:

P(A) = 3/11

the number cube has 6 numbers, then:

P(B) = 1/6

The two events are independent, then:

P(A∩B) = P(A)*P(B) = 3/11 * 1/6 = 1/22

The probability of the spinner stopping at a green section and then rolling a 3 is 1/22