Given:
The original plan for a stage x feet long and x feet wide had to be made smaller to fit the space.
The stage needs to be 6 feet narrower and 4 feet shorter than her original plan.
To find:
The area
Explanation:
According to the problem,
The length of the smaller stage becomes,
[tex]x-6[/tex]The width of the smaller stage becomes,
[tex]x-4[/tex]So, the area becomes,
[tex]\begin{gathered} A=l\times w \\ A=(x-6)(x-4) \\ A=(x^2-10x+24)square\text{ feet.} \end{gathered}[/tex]Final answer:
The correct option is A.
[tex]\left(x-6\right)(x-4)[/tex]The area of the smaller stage is,
[tex]x^2-10x+24[/tex]