Question

i am trying to learn how to do equations like this

Answer 1

The figure is a right triangle since one of its inner angles measures 90°.

Since we are dealing with a right triangle, we can use the following trigonometric identity.

$\tan \theta=\frac{O}{A}$

Where theta is an inner angle of the triangle different from the 90°-angle one, O is the opposite side to theta, and A is the adjacent side to that angle.

Therefore, in our case,

$\theta=55degree,O=y,A=43$

Thus,

$\begin{gathered} \Rightarrow\tan \theta=\tan (55degree)=\frac{y}{43} \\ \Rightarrow y=43\cdot\tan (55dgr)=61.41 \\ \Rightarrow y=61.41 \end{gathered}$

Hence, the answer is y=61.41.