Question

A cube that has edge lengths of 8 inches has a right cylinder cut out of it with a diameter of 8 inches. How much volume remains? Show the calculation that lets your answer and round to the nearest cubic inch.

Answer 1

First, we find the cube volume:

Volume = (a)^3 = (8in)^3 = 512in^3

Then, we find the right cylinder volume

$\begin{gathered} V=\text{ }\pi r^2h=\text{ }\pi(4in^)^2(8in)\text{ = 16in}^2(8in)(\pi) \\ =\text{ 402.12 in}^3 \end{gathered}$

So, the remaining volume will be: 512in3 - 402-12in3 = 109.88in^3

≈ 110 in^3