Question

Find the area of the smaller sector formed by NMP. Round your answer to the nearest hundredth.

Answer 1

Solution:

Given:

$\begin{gathered} \theta=60^0 \\ r=12cm \end{gathered}$

The area of sector is given by;

$\begin{gathered} A=\frac{\theta}{360}\times\pi r^2 \\ A=\frac{60}{360}\times\pi\times12^2 \\ A=\frac{8640\pi}{360} \\ A=24\pi \\ A=75.398 \\ \\ To\text{ the nearest hundredth,} \\ A=75.40cm^2 \end{gathered}$

Therefore, the area of the smaller sector to the nearest hundredth is 75.40 centimeters square.