Find the 17th term of the arithmetic sequence whose common difference is d = 3 and whose first term is a 1 =2(The picture is more understandable)

The rule of the nth term of an arithmetic sequence is
[tex]a_n=a_1+(n-1)d[/tex]a1 is the first term
d is the common difference
n is the position of the term
Since the first term is 2, then
a1 = 2
since the common difference is 3, then
d = 3
since we need to find the 17th term, then
n = 17
Substitute them in the rule above
[tex]\begin{gathered} a_{17}=2+(17-1)(3) \\ a_{17}=2+16(3) \\ a_{17}=2+48 \\ a_{17}=50 \end{gathered}[/tex]The answer is 50