POSSIBLE (x – 5) (2x + 1) = 0 The equation above uses the Zero Product Property to solve for x. Fill in the blanks with the appropriate answers showing the steps for finding x. I-5 = 0 0 and 2.x + 1 (Add or subtract) five from both sides AND (Add or subtract) one from each side (Multiply or divide) each side by two x = 5 and x = -1/2

POSSIBLE x 5 2x 1 0 The equation above uses the Zero Product Property to solve for x Fill in the blanks with the appropriate answers showing the steps for findi class=

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Answer:

[tex]\begin{gathered} \frac{2x}{2}=-\frac{1}{2} \\ x=-\frac{1}{2} \end{gathered}[/tex]

And

[tex]x=5[/tex]

Explanation:

Given the equation;

[tex](x-5)(2x+1)=0[/tex]

Since the product of the two expression equals zero then;

[tex]x-5=0[/tex]

and

[tex]2x+1=0[/tex]

Add 5 to both side of the first one;

[tex]\begin{gathered} x-5+5=0+5 \\ x=5 \end{gathered}[/tex]

and

Subtract 1 from both sides of the second;

[tex]\begin{gathered} 2x+1-1=0-1 \\ 2x=-1 \end{gathered}[/tex]

divide both sides by 2;

[tex]\begin{gathered} \frac{2x}{2}=-\frac{1}{2} \\ x=-\frac{1}{2} \end{gathered}[/tex]

And

[tex]x=5[/tex]

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