Answer:
[tex]\begin{gathered} \frac{2x}{2}=-\frac{1}{2} \\ x=-\frac{1}{2} \end{gathered}[/tex]
And
[tex]x=5[/tex]
Explanation:
Given the equation;
[tex](x-5)(2x+1)=0[/tex]
Since the product of the two expression equals zero then;
[tex]x-5=0[/tex]
and
[tex]2x+1=0[/tex]
Add 5 to both side of the first one;
[tex]\begin{gathered} x-5+5=0+5 \\ x=5 \end{gathered}[/tex]
and
Subtract 1 from both sides of the second;
[tex]\begin{gathered} 2x+1-1=0-1 \\ 2x=-1 \end{gathered}[/tex]
divide both sides by 2;
[tex]\begin{gathered} \frac{2x}{2}=-\frac{1}{2} \\ x=-\frac{1}{2} \end{gathered}[/tex]
And
[tex]x=5[/tex]