ANSWER:
5.57 m/s
STEP-BY-STEP EXPLANATION:
The magnitude of the velocity of each seat is given by the following equation:
[tex]s=\sqrt[]{g\cdot x\cdot\frac{\sin\theta}{\cos\theta}}[/tex]
The value of x is the total extension of the seats from the center of the platform, we can calculate it as follows:
[tex]\begin{gathered} x=\frac{d}{2}+(L\cdot\sin \theta) \\ \text{ Replacing:} \\ x=\frac{8.03}{2}+(3.76\cdot\sin 28.6\text{\degree)} \\ x=5.81 \end{gathered}[/tex]
Replacing:
[tex]\begin{gathered} s=\sqrt[]{9.8\cdot5.81\cdot\frac{\sin \: 28.6}{\cos \: 28.6}} \\ s=5.57\text{ m/s} \end{gathered}[/tex]
The speed is 5.57 m/s
