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Table B
According to the given question, we are to select the table that represents the curve of the function given as:
[tex]y=-2(x+3)^2+4[/tex]For the first table, when x = 0;
y = -2(0 + 3)² + 4
y = -2(3)²+4
y = -2(9) + 4
y = -18 + 4
y = -14
Since the corresponding y value at x = 0 is not equal to 13 as seen in the first table, hence the table A is incorrect
For the second table
When x = -2, we need to check if the resulting y value will be 2
[tex]\begin{gathered} y=-2(-2+3)^2+4 \\ y=-2(1)^2+4 \\ y=-2+4=2 \end{gathered}[/tex]For the second column when x = -1;
[tex]\begin{gathered} y=-2(-1+3)^2+4 \\ y=-2(2)^2+4 \\ y=-2(4)+4 \\ y=-8+4=-4 \end{gathered}[/tex]Since the corresponding y values tally for all the values of x, hence table B represents the given curve.