6.67L
According to Boyle's law, the pressure of a given mass is inversely proportional to its volume provided that the temperature remains constant. Mathematically;
[tex]\begin{gathered} p\alpha\frac{1}{v} \\ p=\frac{k}{v} \\ pv=k \\ p_1v_1=p_2v_2 \end{gathered}[/tex]where:
• p₁ and p₂ are the, initial and fina,l pressure
,• v₁ and v₂ are the ,initial and final volume
Given the following parameters
p₁ = 20atm
p₂ = 30atm
v₁ = 10L
Required
new volume v₂
Substitute the given parameters into the formula to have;
[tex]\begin{gathered} v_2=\frac{p_1v_1}{p_2} \\ v_2=\frac{20\cancel{\text{atm}}\times10L}{30\cancel{\text{atm}}} \\ v_2=\frac{200}{30}L \\ v_2=6.67L \end{gathered}[/tex]Therefore the new volume of the gas is 6.67L
