Determine the new coordinates of the trapezoid.
[tex]A(-8\cdot\frac{1}{2},-8\cdot\frac{1}{2})=A(-4,-4)[/tex][tex]B(-2\cdot\frac{1}{2},2\cdot\frac{1}{2})=B(-1,1)[/tex][tex]C(6\cdot\frac{1}{2},2\cdot\frac{1}{2})=C(3,1)[/tex][tex]D(6\cdot\frac{1}{2},-8\cdot\frac{1}{2})=D(3,-4)[/tex]So coordinates of the trapezoid after dilation is,
A(-4,-4)
B(-1,1)
C(3,1)
D(3,-4)