Answer:
The slope-intercept form of the equation is;
[tex]y=-2x-4[/tex]Explanation:
Given that the equation passes through;
[tex](-1,-2)[/tex]And is parallel to the equation;
[tex]y=-2x-1[/tex]We can derive the slope from the equation parallel to it;
[tex]m=-2[/tex]Using the point-slope formula;
[tex]y=m(x-x_1)+y_1[/tex]Substituting the point and the slope;
[tex]\begin{gathered} y=-2(x+1)-2 \\ y=-2x-2-2 \\ y=-2x-4 \end{gathered}[/tex]Therefore, the slope-intercept form of the equation is;
[tex]y=-2x-4[/tex]