Question

If a single electron has a charge of Q(e)=1.6 X 10^-19 C. Roughly how many electrons are accumulated in 0.00016 C.

Answer 1

Given data:

* The value of the charge given is,

$q=0.00016\text{ C}$

Solution:

Let n be the number of electrons in the given charge.

The net charge in terms of the number of electrons is,

$q=nQ(e)$

where Q(e) is the fundamental value of the charge,

Substituting the known values,

$\begin{gathered} 0.00016=n\times1.6\times10^{-19} \\ n=\frac{0.00016}{1.6\times10^{-19}} \\ n=\frac{1.6\times10^{-4}}{1.6\times10^{-19}} \\ n=1\times10^{-4+19} \\ n=10^{15}\text{ } \end{gathered}$

Thus, the number of electrons in the given charge is 10^(15).