Question

Achemist wishes to mix a solution that is 10% adid. She has on hand 6 Iters of a 8% acid solution and wishes to add some 16% acid solution to obtain the desired 10% acid solution. How much 14% acid solution should she add?Complete the tableLiters ofPercent AcidLiters of

Answer 1

Given

Alchemist wishes to mix a solution that is 10% acid.

She has on hand 6 liter of a 8% acid solution and wishes to add some 16% acid solution to obtain the desired 10% acid solution. H

To find: ow much 146 acid solution should she add?

Explanation:

It is given that,

Alchemist wishes to mix a solution that is 10% acid.

Let x be the amount o acid mixed to obtain the desired 10% solution.

Since she has on hand 6 liters of a 8% acid solution and wishes to add some 16% acid solution to obtain the desired 10% acid solution.

Then,

$\begin{gathered} 6l\text{ }of\text{ }8\%+16\%\text{ }of\text{ }x=10\%\text{ }of\text{ }(6+x) \\ 6\times\frac{8}{100}+\frac{16}{100}\times x=\frac{10}{100}\times(6+x) \\ \frac{48}{100}+\frac{16x}{100}=\frac{10}{100}(6+x) \\ 48+16x=10(6+x) \\ 48+16x=60+10x \\ 16x-10x=60-48 \\ 6x=12 \\ x=\frac{12}{6} \\ x=2 \end{gathered}$

Hence, she should add 2 liters of acid solution.