Respuesta :

We have to solve the integral:

[tex]\int ^4_03x^2e^{x3}dx[/tex]

(Note: the editor does not let write x^3 as the exponent of e)

We will have to do a substitution of variables in order to simplify the solution.

For example, we can see that the derivative of x^3 is 3x^2, that is the factor that multiplies the exponential function. This tells us a clue about a possible substitution.

So we will try the following substitution:

[tex]\begin{gathered} u=x^3\Rightarrow du=3x^2\cdot dx \\ x=0\Rightarrow u=0^3=0 \\ x=4\Rightarrow u=4^3=64 \end{gathered}[/tex]

Then:

[tex]\int ^4_03x^2e^{x3}dx=\int ^4_0e^{x3}(3x^2dx)=\int ^{64}_0e^udu[/tex]

We can solve this integral as:

[tex]\int ^{64}_0e^udu=e^x+C=e^{64}-e^0=6.23\cdot10^{27}[/tex]

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