Question

30 cars are in a race. In how many different ways can cars finish in the top 3 positions?

Answer 1

Given there are 30 cars in a race.

To find in how many ways can cars finish in the top 3 positions.

To find permutations:

$\begin{gathered} ^{30}P_3=\frac{30!}{(30-3)!} \\ =24360 \end{gathered}$

Therefore, there are 24360 ways in which cars can finish in the top 3 positions.