Given the equation :
[tex]16-3x=2\cdot(1+2x)[/tex]Solve for x as following :
[tex]\begin{gathered} 16-3x=2\cdot1+2\cdot2x \\ 16-3x=2+4x \end{gathered}[/tex]Combine the like terms :
[tex]\begin{gathered} -3x-4x=2-16 \\ -7x=-14 \end{gathered}[/tex]Divide both sides by -7
[tex]\begin{gathered} \frac{-7x}{-7}=\frac{-14}{-7} \\ \\ x=2 \end{gathered}[/tex]
