If the given ordered pair satifies the system of equation, then, if you replace the x and y values of the pair the right side of the equation will match with the left side:
In this case, you have:
x = 2/3
y = -5/6
[tex]\begin{gathered} -8(\frac{2}{3})-10(-\frac{5}{6})= \\ -\frac{16}{3}+\frac{50}{6}= \\ -\frac{16}{3}\cdot\frac{2}{2}+\frac{50}{6}= \\ -\frac{32}{6}+\frac{50}{6}= \\ \frac{-32+50}{6}=\frac{18}{6}=3 \end{gathered}[/tex]
the given point is solution of the first equation.
And now, for the second equation:
[tex]\begin{gathered} 6(\frac{2}{3})-6(-\frac{5}{6})= \\ \frac{12}{3}+\frac{30}{6}= \\ 4+5=9 \end{gathered}[/tex]
the given point is also solution of the second equation.
Due to the given pair is solution of both equations, the pair satisfies the system.
YES
