Question

Triangle abc has vertices a (-6,0),b(0,8)and c(6,0) determine the perimeter of triangle abc leave your answer to the nearest tenth.do not include units

Answer 1

The perimeter is 32 units

1) To calculate that perimeter (2) let's calculate the distances, using a formula derived from the Pythagorean Theorem.

$d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2_{}}$

2) Let's calculate the distance from AB, i.e. ( -6,0) and (0,8)

$d\text{ =}\sqrt[]{(0+6)^2+(8-0)^2}=10$

The distance, now from BC ( 0,8) to (6,0)

$d=\sqrt[]{(6-0)^2+(0-8)^2}=10$

And finally CA (6,0) to (-6,0)

$d=\sqrt[]{(-6-6)^2+(0-0)^2}=12$

3) The Perimeter then, adding all the lengths will be (2P) Is: 10 +10 +12 = 32