How many moles of potassium are needed to react completely with 12.8 moles of magnesium bromide?

Answer:
25.6 moles of K.
Explanation:
In the chemical equation you can see that 2 moles of potassium (K) react with 1 mol of magnesium bromide (MgBr2), so based on this information let's find the number of moles of K that we required by 12.8 moles of MgBr2:
[tex]12.8\text{ moles MgBr}_2\cdot\frac{2\text{ moles K}}{1\text{ mol MgBr}_2}=25.6\text{ moles K.}[/tex]The answer would be that we require 25.6 moles of K.