The equation of a parabola with vertex (h,k) is:
[tex]f(x)=c(x-h)^2+k[/tex]
Where c is a constant.
Notice that the graph of this parabola has a y-intercept of -2 and the vertex has coordinates (1,-3). Replace h=1 and k=-3:
[tex]f(x)=c(x-1)^2-3[/tex]
Since f(0)=-2, replace x=0 and f(0)=-2 to find the value of the constant c:
[tex]\begin{gathered} f(0)=c(0-1)^2-3 \\ \Rightarrow-2=c-3 \\ \Rightarrow c=3-2 \\ \Rightarrow c=1 \end{gathered}[/tex]
Then, the equation for the given graph, is:
[tex]f(x)=(x-1)^2-3[/tex]
Which can be expanded as follows:
[tex]\begin{gathered} f(x)=x^2-2x+1-3 \\ \Rightarrow f(x)=x^2-2x-2 \end{gathered}[/tex]
Therefore, two possible (equivalent) answers are:
f(x) = x^2-2x-2
f(x) = (x-1)^2-3