Question

What is the relative intensity of a sound wave with an intensity of 0.00458 W/m²?9.66 dB-143 dB96.6 dB-14.3 dB

Answer 1

Given

The intensity is

$I_=0.00458\text{ W/m}^2$

To find

The relative intensity

Explanation

The relative intensity is given by

$P=10log(\frac{I}{I_o})$

Here,

$I_o=10^{-12}$

Thus,

$\begin{gathered} P=10log(\frac{0.00458}{10^{-12}}) \\ \Rightarrow P=96.6\text{ dB} \end{gathered}$

Conclusion

The relative intensity is 96.6 dB