can you find x for this problem i want to make sure my answers right

Given:
In a right triangle,
The angle is 60 degrees.
The length of the opposite side is,
[tex]2\sqrt[]{3}[/tex]The length of the adjacent side is 2.
The hypotenuse side is x.
To find the value of x:
Using the trigonometric ratio of sine,
[tex]\begin{gathered} \sin \theta=\frac{\text{Opp}}{\text{Hyp}} \\ \sin 60^{\circ}=\frac{2\sqrt[]{3}}{x} \\ x=\frac{2\sqrt[]{3}}{\sin 60^{\circ}} \\ x=\frac{2\sqrt[]{3}}{\frac{\sqrt[]{3}}{2}} \\ x=\frac{2}{\frac{1}{2}} \\ x=4 \end{gathered}[/tex]Hence, the value of x is 4.