EXPLANATION
Given the pyramid with a square base where the side length is = 19.3 an h= 16.2 ft.
The equation to find the volume is as follows:
[tex]\text{Volume = }\frac{1}{3}a^2h[/tex]where a=side length = 19.3ft and h=16.2
Replacing terms:
[tex]\text{Volume = }\frac{1}{3}\cdot19.3^2\cdot16.2[/tex]Solving the power:
[tex]\text{Volume = }\frac{1}{3}\cdot372.49\cdot16.2[/tex]Multiplying terms:
[tex]\text{Volume = 2,011.44 ft}^3[/tex]Rounding to the nearest tenth:
[tex]\text{Volume = 2,011.4 ft}^3[/tex]