Examine the graph of f(x) and the table that contains values of g(x).Which function has a greater average rate of change over the interval 0≤x≤1?

Let's determine the rate of change of the two functions at 0 ≤ x ≤ 1.
For f(x),
Point 1: 0, -4
Point 2: 1, 2
[tex]\text{ Rate of change = slope = }\frac{\text{y}_2\text{ - y}_1}{\text{ x}_2\text{ - x}_1}[/tex][tex]\text{ = }\frac{2\text{ - \lparen-4\rparen}}{1\text{ - 0}}\text{ = }\frac{2\text{ + 4}}{1}\text{ = }\frac{6}{1}[/tex][tex]\text{ Rate of change of f\lparen x\rparen = 6}[/tex]For g(x),
Point 1: 0, 3
Point 2: 1, 9
[tex]\text{ Rate of change = }\frac{9\text{ - 3}}{1\text{ - 0}}\text{ = }\frac{6}{1}[/tex][tex]\text{ Rate of change of g\lparen x\rparen = 6}[/tex]Therefore, both functions has the same average rate of change over this interval.
The answer is CHOICE C.