We know that Jasmine ran 10 miles in 60 minutes, and we want to know the rate at which she ran.
We remember that:
[tex]v=\frac{d}{t}[/tex]where v represents speed, d distance and t time. We get that the rate of Jasmine is
[tex]\begin{gathered} v=\frac{10}{60}mi/\min \\ =\frac{1}{6}mi/\min \\ =0.1\bar{6}mi/\min \end{gathered}[/tex]We will assume that Katie ran 5 miles, and that she ran at a rate that was 5 minutes per mile more than Jasmine.
For determining for how many minutes did Katie run, we will clear out the variable t on the equation above shown. The rate of Katie is:
[tex]v=0.1\bar{6}+5=5.1\bar{6}mi/\min [/tex]Now, we get:
[tex]\begin{gathered} v\cdot t=d \\ t=\frac{d}{v}=\frac{5}{5.1\bar{6}}=0.9677\min \end{gathered}[/tex]This means that Katie will take 0.97 minutes (approximately) to run 5 miles.