Height of PQ=18mHeight of RS=???Length of QS= 25mThe angle of elevation of R from P is 32°Calculate the height in m of RS.A. 4.38B. 15.62C. 33.62D. 40.00

For the given diagram, we will find the length of RS
We will modify the diagram, it will be as shown in the following figure:
PO is parallel to QS, and equal in length to it
The angle of elevation of R from P is 32°
so, the measure of angle (OPR) = 32°
For the triangle OPR:
It is a right triangle at O
OP = 25 m
m∠OPR = 32°
So,
[tex]\begin{gathered} \tan (\text{OPR)}=\frac{opposite}{adjacent}=\frac{OR}{OP} \\ \tan 32=\frac{OR}{25} \\ \\ OR=25\cdot\tan 32 \end{gathered}[/tex]The length of RS = OR + OS
OS = QP = 18 m
so,
[tex]\begin{gathered} RS=18+25\cdot\tan 32=18+15.62 \\ \\ RS=33.62m \end{gathered}[/tex]So, the answer will be option C. 33.62