Question

-32, 62, -88, -46, -96 I need help finding the average of the following integers

Answer 1

Given the integers:

-32, 62, -88, -46, -96

Let's find the average of the given integers.

The average can be said to be the mean of the numbers.

To find the average of the integers, apply the formula:

$\text{Average}=\frac{\text{ sum of integers}}{\text{ number of integrs}}$

Where:

Sum of integers = -32 + 62 + (-88) + (-46) + (-96)

= -32 + 62 - 88 - 46 - 96

= -200

Number of integers = 5

To find the average, we have:

$\text{Average}=\frac{-200}{5}=-40$

Therefore, the mean of the given set of integers is -40.

ANSWER:

-40