Answer:
x=8 and y=-6
Explanation:
Given the system of equations:
[tex]\begin{gathered} 2x+y=10 \\ 4x+5y=2 \end{gathered}[/tex]Make y the subject of the first equation:
[tex]y=10-2x[/tex]Substitute y=10-2x into the second equation:
[tex]\begin{gathered} 4x+5(10-2x)=2 \\ 4x+50-10x=2 \\ -6x=2-50 \\ -6x=-48 \\ x=\frac{-48}{-6} \\ x=8 \end{gathered}[/tex]Recall that y=10-2x
[tex]\begin{gathered} y=10-2x \\ =10-2(8) \\ =10-16 \\ y=-6 \end{gathered}[/tex]The solution to the system of equations is : x=8 and y=-6
