Given:
There are given the equation:
[tex]x^2+y^2-4x+4y+4=0[/tex]
Explanation:
To find the radius of the circle, first, we need to write the given equation into the vertex for:
Then,
[tex]\begin{gathered} x^{2}+y^{2}-4x+4y+4=0 \\ (x-2)^2+(y+2)^2=2^2 \end{gathered}[/tex]
Final answer:
According to the vertex form of the circle:
The value of the radius is 2.
