For the minimum value, the first derivative of function is equate to zero and value of second derivative is posiive.
Determine the first derivative of cost function.
[tex]\begin{gathered} \frac{d}{dx}c(x)=\frac{d}{dx}(0.2x^2-36x+8122) \\ =0.4x-36 \end{gathered}[/tex]For maximum and minimu value,
[tex]\begin{gathered} 0.4x-36=0 \\ x=\frac{36}{0.4} \\ =90 \end{gathered}[/tex]Determie the second derivative of the cost function.
[tex]\begin{gathered} \frac{d^2}{dx^2}c(x)=\frac{d^2}{dx^2}(0.2x^2-36x+8122) \\ =0.4 \end{gathered}[/tex]The second derivative of cost function is positive for all value of x. So x = 90 machines corresponds to the minimum value of function.
Answer: 90 machines