Question

The electric field between two parallel plates connected to a 45 V battery (which produces a 45 V difference in potential between the plates) is 1500 N/C. How far apart are the plates?

Answer 1

ANSWER is 0.03m

$d=\frac{v}{e}=\frac{45}{1500}=0.03$

where d is the distance between the plates, v is difference in potential between the plates, e is electric field.