We have the expression
4(x^2 - 2x) - 2(x^2 - 3)
Firstly, open the parentheses
4 * x^2 - 4 * 2x - 2*x^2 -2 * (-3)
4x^2 - 8x - 2x^2 + 6
Secondly, collect the like terms
4x^2 - 2x^2 - 8x + 6
2x^2 - 8x + 6
2 is common in the expression, hence, 2 can be factorize out
2(x^2 - 4x + 3)
Solve the quadratic function in the parenthesis using factorization method
x^2 - 4x + 3
Factors of 3 are : 1 and 3, -1 and -3
Its only -1 and -3 that will give us -4 when add and give us +3 when multiply
x^2 - x - 3x + 3
x(x - 1) -3(x - 1)
(x - 1)(x - 3)
The new expression becomes
2[ (x -1)(x-3)]
The answer is OPTION A
