Question

A truck starts at rest and has a constantacceleration of 2.10 m/s^2for a time span of20.0 s.(a) How far has the truck traveled at the endof the 20.0 s?(b) What is the speed of the truck at the endof the 20.0 s?

Answer 1

We will have the following:

a) The truck will travel:

$x=(0m)+(0m/s)(20s)+\frac{1}{2}(2.10m/s^2)(20.0s)^2\Rightarrow x=420m$

So, the truck moved 420 meters.

b) The final speed the truck will have:

$v=(0m/s)+(2.10m/s^2)(20s)\Rightarrow v=_{}42m/s$

So, the final speed of the truck will be 42 m/s.