Solution
For this case we have the following sample space:
3 red balls
4 green balls
2 yellow balls
And we have the following sequence given:
red, red, green, yellow
And we want the probability that she picks is green after these selection so then we have this:
After the first selection we have 8 balls (2 red, 4 green and 2 yellow)
After the second selection we have just 7 balls (1 red ,4 green and 2 yellow)
After the third one we have just 6 balls (1 red ,3 green and 2 yellow)
After the fourth one we have 5 balls left (1 red 3 green and 1 yellow)
Then the probability of getting a green one after this procedure is:
3/5 = 0.6= 60%
Answer:
D