Hello! I need some assistance with this homework question for precalculus, please?HW Q30

Answer:
[tex]\begin{equation*} 2\log_3z \end{equation*}[/tex]Explanation:
Given the below logarithmic expression;
[tex]log_3z^2[/tex]To simplify the above, we'll have to apply the below power rule of logarithm rule;
[tex]log_am^n=nlog_am[/tex]Applying the above logarithm rule, we'll have;
[tex]\log_3z^2=2\log_3z[/tex]