Find the value of the car after 7years and after 12 years. Round your answers to the nearest dollar as necessary

Solution:
The function is given below as
[tex]v(t)=24,500(0.80)^t[/tex]Step 1:
To figure out the value of the car after 7 years, we will put t=7
[tex]\begin{gathered} v(t)=24,500(0.80)^{t} \\ v(t)=24,500(0.80)^7 \\ v(t)=5,138 \end{gathered}[/tex]Hence,
The value of the car after 7 years will be
[tex]\Rightarrow\text{ \$}5138[/tex]Step 2:
To figure out the value of the car after 12 years, we will put t=12
[tex]\begin{gathered} v(t)=24,500(0.80)^{t} \\ v(12)=24500(0.80)^{12} \\ v(12)=1683.63 \\ v(12)\approx\text{ \$}1684 \end{gathered}[/tex]Hence,
The value of the car after 12 years to the nearest dollar will be
[tex]\Rightarrow\text{ \$}1684[/tex]