Question

13) Mr. Jameson is making a pool cover for his rectangular pool. He first draws a blue print where the scale is 2 in =8 feet. If the actual pool is 16 feet by 20 feet, what is the perimeter of the pool on the blueprint?

Answer 1

Given:

$\begin{gathered} Blue-print: \\ 2in=8feet \\ Actual-pool \\ length(l)=16ft \\ width(w)=20ft \end{gathered}$

To Determine: The perimter of the pool on the blueprint

Solution

$\begin{gathered} Perimeter(Pool)=2l+2w \\ =2\times16ft+2\times20ft \\ =32ft+40ft \\ =72ft \\ 2in=8ft \\ 8ft=2in \\ 72ft=72ft\times\frac{2in}{8ft} \\ =18in \end{gathered}$

Hence, the perimeter of the pool on the blueprint is 18 inches