Given:
[tex]\begin{gathered} 2x-3y=13\ldots\ldots(1) \\ x=2y+7\ldots\ldots\ldots(2) \end{gathered}[/tex]To find x and y:
Using substitution method,
Substitute equation (2) in (1) we get,
[tex]\begin{gathered} 2(2y+7)-3y=13_{} \\ 4y+14-3y=13 \\ y+14=13 \\ y=-1 \end{gathered}[/tex]Substitute y=-1 in equation (2) we get,
[tex]\begin{gathered} x=2(-1)+7 \\ x=-2+7 \\ x=5 \end{gathered}[/tex]Hence, the solutions are x=5 and y= -1.