The area of an oblique pyramid is one-third of the product of the area of the base and its height.
Thus, we substitute the values of the dimensions to the following equation.
[tex]\begin{gathered} V=\frac{1}{3}Ah \\ V=\frac{1}{3}LW\text{h} \\ V=\frac{1}{3}(16)(3)(10) \end{gathered}[/tex]
Simplify the expression by cancelling out the 3 from the numerator and the denominator. Thus, we get the following.
[tex]\begin{gathered} V=16(10) \\ V=160 \end{gathered}[/tex]
Therefore, the volume of the pyramid is 160 in³.
