Respuesta :

Recall that

[tex]\log _ax[/tex]

is defined for all positive real numbers, therefore:

[tex]\text{Dom}(0.7\log _3(x))=(0,\infty)\text{.}[/tex]

Also, since the range of log_3(x) is all real numbers, then:

[tex]Ran(0.7\log _3(x))=(-\infty,\infty).[/tex]

Now, to find the x-intercept, we set y(x)=0:

[tex]0.7\log _3(x)=0.[/tex]

Dividing the above equation by 0.7 we get:

[tex]\begin{gathered} \frac{0.7}{0.7}\log _3(x)=\frac{0}{0.7}, \\ \log _3(x)=0. \end{gathered}[/tex]

Solving the above equation for x we get:

[tex]\begin{gathered} 3^{\log _3(x)}=3^0, \\ x=1. \end{gathered}[/tex]

Therefore, the x-intercept has coordinates (1,0).

Since the function is only defined at (0,∞), there is no y-intercept.

Finally, the function has an asymptote at x=0.

Answer:

Domain:

[tex](0,\infty).[/tex]

Range:

[tex](-\infty,\infty).[/tex]

X-intercept:

[tex](1,0)\text{.}[/tex]

Y-intercept: There is no y-intercept.

Asymptote:

[tex]x=0.[/tex]

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