Find the volume of this cone.Use 3 for T.10 ft=115 ftTr²hV=3Hint: The radius (1) is1/2 of the diameter.V ~ [?]ft3

Given:-
[tex]V=\frac{\pi r^2h}{3}[/tex]To find the volume of the cone.
From the given image it is clear,
[tex]h=5,r=5[/tex]So now we substitute the known values. so we get,
[tex]\begin{gathered} V=\frac{\pi r^2h}{3} \\ V=\frac{3(5)^25}{3} \\ V=5^3 \\ V=125 \end{gathered}[/tex]So the required volume is 125ft^3.