Question

4) Find the area of each composite figure. 2.5 in 2.5 in 6 in in? 4.2 in А = square A trapezoid ina А figure 1/1

Answer 1

The figure is a combination of a square and a trapezoid;

Thus, we first look for the area of a square using the formula below;

$\begin{gathered} A_{square}=length\times length \\ \text{Where the length of the square is 2.5in} \\ A_{square}=2.5\times2.5 \\ A_{square}=6.25in^2 \end{gathered}$

Answer: The area of the square is 6.25 square inches.

Also, we find the area of the trapezoid using the formula below;

$\begin{gathered} A_{trapezoid}=\frac{1}{2}(a+b)h \\ \text{Where a and b are the upper length and the bottom length respectively } \\ a\text{ is the length of the square = 2.5in} \\ b=\text{ 4.2in} \\ \text{h is the height = 6in} \\ A_{trapezoid}=\frac{1}{2}(2.5+4.2)6 \\ A_{trapezoid}=3(6.7) \\ A_{trapezoid}=20.1in^2 \end{gathered}$

Answer: The area of the trapezoid is 20.1 square inches.

$\begin{gathered} A_{figure}=A_{square}+A_{trapezoid} \\ A_{figure}=6.25in^2+20.1in^2 \\ A_{figure}=26.35in^2 \end{gathered}$

Answer: The area of the figure is 26.35 square inches.