In the circle. If two chords intersect at a point inside the circle, then the product of their parts are equal
By using this fact, then
[tex]12\times x=15\times(x-1)[/tex]
Let us solve to find x
[tex]\begin{gathered} 12x=15(x)-15(1) \\ 12x=15x-15 \end{gathered}[/tex]
Subtract 15 x from both sides
[tex]\begin{gathered} 12x-15x=15x-15x-15 \\ -3x=-15 \end{gathered}[/tex]
Divide both sides by -3
[tex]\begin{gathered} \frac{-3x}{-3}=\frac{-15}{-3} \\ x=5 \end{gathered}[/tex]
The value of x is 5
