Question

A projectile is fired vertically upward with an initial velocity of 190 m/s. Find the maximum height of the projectile

Answer 1

ANSWER

$1841.84\text{ m}$

EXPLANATION

Parameteters given:

Initial velocity = 190 m/s

To find the maximum height, we apply the formula for the maximum height of a projectile:

$H=\frac{u^2\sin ^2\theta}{2g}$

where u = initial velocity

θ = angle with the horizontal

g = acceleration due to gravity = 9.8 m/s²

From the question, the projectile is fired vertically upward. This means that the projectile will make a 90° angle with the horizontal.

Therefore, we have that the maximum height of the projectile is:

$\begin{gathered} H=\frac{190^2\cdot\sin ^2(90)}{2\cdot9.8} \\ H=1841.84\text{ m} \end{gathered}$