Question

Point A is located at (4x -8, y-11).Point B is located at (4x +8, y-17).What is slope of the line?

Answer 1

Given:

Point A is located at (4x -8, y-11). Point B is located at (4x +8, y-17).

To find:

The slope of the line.

Solution:

It is known that the slope of the line passing through the points (x1, y1) and (x2, y2) is given by:

$m=\frac{y_2-y_1}{x_2-x_1}$

So, the required slope is:

$\begin{gathered} m=\frac{(y-17)-(y-11)}{(4x+8)-(4x-8)} \\ =\frac{y-17-y+11}{4x+8-4x+8} \\ =\frac{-6}{16} \\ =\frac{-3}{8} \end{gathered}$

Thus, the slope of the line is -3/8.