Answer:
y=(-1/3)x+3
Explanation:
Given the equation:
[tex]x+3y=9[/tex]To write it in the slope-intercept form, make y the subject:
[tex]\begin{gathered} 3y=-x+9 \\ \implies y=-\frac{1}{3}x+\frac{9}{3} \\ \implies y=-\frac{1}{3}x+3 \end{gathered}[/tex]The slope-intercept form is y=-1/3x+3.
Next, we graph the line using the intercepts.
[tex]\begin{gathered} \text{When }x=0,y=3\implies(0,3) \\ \text{When y=0, }x=9\implies(9,0) \end{gathered}[/tex]Join the points (0,3) and (9,0) using a straight line by following these steps:
• Identify the point (0,3) i.e. 3 on the y-axis
,• Identify the point (9,0) i.e. 9 on the x-axis
,• Join the two points with a straight line
Since a graph cannot be uploaded currently, follow the steps above.
