Question

simplify the expression $\sqrt{ \frac{25y ^{2?} }{6x} }$show your work

Answer 1

we have

$\sqrt[]{\frac{25y^2}{6x}}$

Remember that

25=5^2

substitute

$\begin{gathered} \sqrt[]{\frac{5^2y^2}{6x}} \\ \\ 5y\sqrt[]{\frac{1}{6x}} \\ \\ \frac{5y}{\sqrt[]{6x}} \\ \\ \frac{5y\sqrt[]{6x}}{6x} \end{gathered}$